x^2-1.6x+0.36=0

Solution for x^2-1.6x+0.36=0 equation:

x^2-1.6x+0.36=0

a = 1; b = -1.6; c = +0.36;
Δ = b2-4ac
Δ = -1.62-4·1·0.36
Δ = 1.12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{1.12}}{2*1}=\frac{1.6-\sqrt{1.12}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{1.12}}{2*1}=\frac{1.6+\sqrt{1.12}}{2}
$